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 Font size: Tiny Small Normal Large Huge Font colour [quote="mathead"]Can anyone help me to generate the Gegenbauer polynomials if we know that P_0=1, P_1=x and P_(i+1)=((2i+n-2)x*P_i-i*P_(i-1))/(i+n-2). Where n is a variable and every P_i(1)=1;[/quote]
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Topic review - gegenbauer polynomials
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 Post subject: gegenbauer polynomials
 Can anyone help me to generate the Gegenbauer polynomials if we know that P_0=1, P_1=x and P_(i+1)=((2i+n-2)x*P_i-i*P_(i-1))/(i+n-2). Where n is a variable and every P_i(1)=1; Can anyone help me to generate the Gegenbauer polynomials if we know that P_0=1, P_1=x and P_(i+1)=((2i+n-2)x*P_i-i*P_(i-1))/(i+n-2). Where n is a variable and every P_i(1)=1;
 Posted: Thu Aug 03, 2017 11:08 am

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