# Singular

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Topic review - primary and secondary invariants
Author Message
 johnunmx
 Post subject: primary and secondary invariants
 Hi, all: I am new to Singular, and what I want to do is to generate all primary and secondary invariants of a polynomial within some total degree, which is symmetrized under a known group. For instance, v=f(r12,r13,r23), and the group is s3, whose elements are just the same as in the permutation group of S3. My script is following as: ring R=0,(x,y,z),dp; > matrix A1[3][3]=1,0,0,0,1,0,0,0,1;> matrix A2[3][3]=1,0,0,0,0,1,0,1,0; > matrix A3[3][3]=0,0,1, 0,1,0, 1,0,0; > matrix A4[3][3]=0,1,0, 1,0,0, 0,0,1; > matrix A5[3][3]=0,0,1, 1,0,0, 0,1,0; > matrix A6[3][3]=0,1,0, 0,0,1, 1,0,0; Then I do not know how to make S=(A1, A2, A3, A4, A5, A6). After this, I think I can get the invariants usingB(1..3)=invariant_ring(S);Am I right? Thanks in advance.BestJohn Hi, all: I am new to Singular, and what I want to do is to generate all primary and secondary invariants of a polynomial within some total degree, which is symmetrized under a known group. For instance, v=f(r12,r13,r23), and the group is s3, whose elements are just the same as in the permutation group of S3. My script is following as: ring R=0,(x,y,z),dp; > matrix A1[3][3]=1,0,0,0,1,0,0,0,1;> matrix A2[3][3]=1,0,0,0,0,1,0,1,0; > matrix A3[3][3]=0,0,1, 0,1,0, 1,0,0; > matrix A4[3][3]=0,1,0, 1,0,0, 0,0,1; > matrix A5[3][3]=0,0,1, 1,0,0, 0,1,0; > matrix A6[3][3]=0,1,0, 0,0,1, 1,0,0; Then I do not know how to make S=(A1, A2, A3, A4, A5, A6). After this, I think I can get the invariants usingB(1..3)=invariant_ring(S);Am I right? Thanks in advance.BestJohn
 Posted: Thu Sep 26, 2013 8:00 am

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