Post new topic Reply to topic  [ 1 post ] 
Author Message
 Post subject: primary and secondary invariants
PostPosted: Thu Sep 26, 2013 8:00 am 
Hi, all:

I am new to Singular, and what I want to do is to generate all primary and secondary invariants of a polynomial within some total degree, which is symmetrized under a known group. For instance, v=f(r12,r13,r23), and the group is s3, whose elements are just the same as in the permutation group of S3. My script is following as:

ring R=0,(x,y,z),dp;
> matrix A1[3][3]=1,0,0,0,1,0,0,0,1;
> matrix A2[3][3]=1,0,0,0,0,1,0,1,0;
> matrix A3[3][3]=0,0,1, 0,1,0, 1,0,0;
> matrix A4[3][3]=0,1,0, 1,0,0, 0,0,1;
> matrix A5[3][3]=0,0,1, 1,0,0, 0,1,0;
> matrix A6[3][3]=0,1,0, 0,0,1, 1,0,0;

Then I do not know how to make S=(A1, A2, A3, A4, A5, A6). After this, I think I can get the invariants using
B(1..3)=invariant_ring(S);

Am I right? Thanks in advance.

Best

John


Report this post
Top
  
Reply with quote  
Display posts from previous:  Sort by  
Post new topic Reply to topic  [ 1 post ] 

You can post new topics in this forum
You can reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot post attachments in this forum

It is currently Thu Dec 14, 2017 10:51 pm
cron
Powered by phpBB © 2000, 2002, 2005, 2007 phpBB Group