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 Author: shengyushen [ Fri Feb 06, 2015 11:11 am ] Post subject: unspecified minpoly Dear all: I am learning using singular , and I run the following script in singular> ring A1=(2^3,a),x,dp;> minpoly ; 1*a^3+1*a^1+1*a^0> ring A2=(2,a),x,dp; // ** redefining A2 **> minpoly ; 0I am confused by it, I have not specified a monopoly for both A1 and A2 rings, but the A1 have a monopoly already, but not the A2.Does this means that the A1 have only 1 monopoly so we don't need to specify it?Shengyu Shen

 Author: pankajsejwal [ Mon May 30, 2016 8:28 am ] Post subject: Re: unspecified minpoly ring r1 = (2^3,a),x,dp;is generated by a3+a+1 working as maximal ideal and it is a known fact and also stored in Singular CAS,https://github.com/Singular/Sources/tre ... y/gftables

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