1 | /* emacs edit mode for this file is -*- C++ -*- */ |
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2 | /* $Id$ */ |
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3 | |
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4 | //{{{ docu |
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5 | // |
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6 | // cf_chinese.cc - algorithms for chinese remaindering. |
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7 | // |
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8 | // Used by: cf_gcd.cc, cf_linsys.cc |
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9 | // |
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10 | // Header file: cf_algorithm.h |
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11 | // |
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12 | //}}} |
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13 | |
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14 | #include "config.h" |
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15 | |
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16 | #ifdef HAVE_NTL |
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17 | #include "NTLconvert.h" |
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18 | #endif |
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19 | |
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20 | #include "cf_assert.h" |
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21 | #include "debug.h" |
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22 | |
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23 | #include "canonicalform.h" |
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24 | #include "cf_iter.h" |
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25 | |
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26 | |
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27 | //{{{ void chineseRemainder ( const CanonicalForm & x1, const CanonicalForm & q1, const CanonicalForm & x2, const CanonicalForm & q2, CanonicalForm & xnew, CanonicalForm & qnew ) |
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28 | //{{{ docu |
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29 | // |
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30 | // chineseRemainder - integer chinese remaindering. |
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31 | // |
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32 | // Calculate xnew such that xnew=x1 (mod q1) and xnew=x2 (mod q2) |
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33 | // and qnew = q1*q2. q1 and q2 should be positive integers, |
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34 | // pairwise prime, x1 and x2 should be polynomials with integer |
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35 | // coefficients. If x1 and x2 are polynomials with positive |
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36 | // coefficients, the result is guaranteed to have positive |
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37 | // coefficients, too. |
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38 | // |
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39 | // Note: This algorithm is optimized for the case q1>>q2. |
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40 | // |
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41 | // This is a standard algorithm. See, for example, |
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42 | // Geddes/Czapor/Labahn - 'Algorithms for Computer Algebra', |
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43 | // par. 5.6 and 5.8, or the article of M. Lauer - 'Computing by |
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44 | // Homomorphic Images' in B. Buchberger - 'Computer Algebra - |
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45 | // Symbolic and Algebraic Computation'. |
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46 | // |
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47 | // Note: Be sure you are calculating in Z, and not in Q! |
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48 | // |
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49 | //}}} |
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50 | void |
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51 | chineseRemainder ( const CanonicalForm & x1, const CanonicalForm & q1, const CanonicalForm & x2, const CanonicalForm & q2, CanonicalForm & xnew, CanonicalForm & qnew ) |
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52 | { |
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53 | DEBINCLEVEL( cerr, "chineseRemainder" ); |
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54 | |
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55 | DEBOUTLN( cerr, "log(q1) = " << q1.ilog2() ); |
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56 | DEBOUTLN( cerr, "log(q2) = " << q2.ilog2() ); |
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57 | |
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58 | // We calculate xnew as follows: |
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59 | // xnew = v1 + v2 * q1 |
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60 | // where |
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61 | // v1 = x1 (mod q1) |
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62 | // v2 = (x2-v1)/q1 (mod q2) (*) |
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63 | // |
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64 | // We do one extra test to check whether x2-v1 vanishes (mod |
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65 | // q2) in (*) since it is not costly and may save us |
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66 | // from calculating the inverse of q1 (mod q2). |
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67 | // |
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68 | // u: v1 (mod q2) |
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69 | // d: x2-v1 (mod q2) |
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70 | // s: 1/q1 (mod q2) |
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71 | // |
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72 | CanonicalForm v2, v1; |
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73 | CanonicalForm u, d, s, dummy; |
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74 | |
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75 | v1 = mod( x1, q1 ); |
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76 | u = mod( v1, q2 ); |
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77 | d = mod( x2-u, q2 ); |
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78 | if ( d.isZero() ) |
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79 | { |
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80 | xnew = v1; |
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81 | qnew = q1 * q2; |
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82 | DEBDECLEVEL( cerr, "chineseRemainder" ); |
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83 | return; |
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84 | } |
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85 | (void)bextgcd( q1, q2, s, dummy ); |
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86 | v2 = mod( d*s, q2 ); |
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87 | xnew = v1 + v2*q1; |
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88 | |
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89 | // After all, calculate new modulus. It is important that |
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90 | // this is done at the very end of the algorithm, since q1 |
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91 | // and qnew may refer to the same object (same is true for x1 |
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92 | // and xnew). |
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93 | qnew = q1 * q2; |
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94 | |
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95 | DEBDECLEVEL( cerr, "chineseRemainder" ); |
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96 | } |
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97 | //}}} |
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98 | |
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99 | //{{{ void chineseRemainder ( const CFArray & x, const CFArray & q, CanonicalForm & xnew, CanonicalForm & qnew ) |
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100 | //{{{ docu |
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101 | // |
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102 | // chineseRemainder - integer chinese remaindering. |
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103 | // |
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104 | // Calculate xnew such that xnew=x[i] (mod q[i]) and qnew is the |
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105 | // product of all q[i]. q[i] should be positive integers, |
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106 | // pairwise prime. x[i] should be polynomials with integer |
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107 | // coefficients. If all coefficients of all x[i] are positive |
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108 | // integers, the result is guaranteed to have positive |
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109 | // coefficients, too. |
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110 | // |
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111 | // This is a standard algorithm, too, except for the fact that we |
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112 | // use a divide-and-conquer method instead of a linear approach |
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113 | // to calculate the remainder. |
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114 | // |
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115 | // Note: Be sure you are calculating in Z, and not in Q! |
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116 | // |
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117 | //}}} |
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118 | void |
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119 | chineseRemainder ( const CFArray & x, const CFArray & q, CanonicalForm & xnew, CanonicalForm & qnew ) |
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120 | { |
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121 | DEBINCLEVEL( cerr, "chineseRemainder( ... CFArray ... )" ); |
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122 | |
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123 | ASSERT( x.min() == q.min() && x.size() == q.size(), "incompatible arrays" ); |
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124 | CFArray X(x), Q(q); |
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125 | int i, j, n = x.size(), start = x.min(); |
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126 | |
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127 | DEBOUTLN( cerr, "array size = " << n ); |
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128 | |
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129 | while ( n != 1 ) |
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130 | { |
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131 | i = j = start; |
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132 | while ( i < start + n - 1 ) |
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133 | { |
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134 | // This is a little bit dangerous: X[i] and X[j] (and |
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135 | // Q[i] and Q[j]) may refer to the same object. But |
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136 | // xnew and qnew in the above function are modified |
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137 | // at the very end of the function, so we do not |
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138 | // modify x1 and q1, resp., by accident. |
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139 | chineseRemainder( X[i], Q[i], X[i+1], Q[i+1], X[j], Q[j] ); |
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140 | i += 2; |
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141 | j++; |
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142 | } |
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143 | |
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144 | if ( n & 1 ) |
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145 | { |
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146 | X[j] = X[i]; |
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147 | Q[j] = Q[i]; |
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148 | } |
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149 | // Maybe we would get some memory back at this point if |
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150 | // we would set X[j+1, ..., n] and Q[j+1, ..., n] to zero |
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151 | // at this point? |
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152 | |
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153 | n = ( n + 1) / 2; |
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154 | } |
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155 | xnew = X[start]; |
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156 | qnew = Q[q.min()]; |
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157 | |
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158 | DEBDECLEVEL( cerr, "chineseRemainder( ... CFArray ... )" ); |
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159 | } |
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160 | //}}} |
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161 | |
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162 | CanonicalForm Farey_n (CanonicalForm N, const CanonicalForm P) |
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163 | //"USAGE: Farey_n (N,P); P, N number; |
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164 | //RETURN: a rational number a/b such that a/b=N mod P |
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165 | // and |a|,|b|<(P/2)^{1/2} |
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166 | { |
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167 | //assume(P>0); |
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168 | // assume !isOn(SW_RATIONAL): mod is a no-op otherwise |
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169 | if (N<0) N +=P; |
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170 | CanonicalForm A,B,C,D,E; |
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171 | E=P; |
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172 | B=1; |
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173 | while (!N.isZero()) |
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174 | { |
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175 | if (2*N*N<P) |
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176 | { |
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177 | On(SW_RATIONAL); |
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178 | N /=B; |
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179 | Off(SW_RATIONAL); |
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180 | return(N); |
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181 | } |
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182 | D=mod(E , N); |
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183 | C=A-(E-mod(E , N))/N*B; |
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184 | E=N; |
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185 | N=D; |
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186 | A=B; |
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187 | B=C; |
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188 | } |
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189 | return(0); |
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190 | } |
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191 | |
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192 | CanonicalForm Farey ( const CanonicalForm & f, const CanonicalForm & q ) |
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193 | { |
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194 | int is_rat=isOn(SW_RATIONAL); |
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195 | Off(SW_RATIONAL); |
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196 | Variable x = f.mvar(); |
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197 | CanonicalForm result = 0; |
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198 | CanonicalForm c; |
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199 | CFIterator i; |
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200 | #ifdef HAVE_NTL |
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201 | ZZ NTLq= convertFacCF2NTLZZ (q); |
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202 | ZZ bound; |
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203 | SqrRoot (bound, NTLq/2); |
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204 | #endif |
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205 | for ( i = f; i.hasTerms(); i++ ) |
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206 | { |
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207 | c = i.coeff(); |
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208 | if ( c.inCoeffDomain()) |
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209 | { |
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210 | #ifdef HAVE_NTL |
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211 | if (c.inZ() && isOn (SW_USE_NTL)) |
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212 | { |
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213 | ZZ NTLc= convertFacCF2NTLZZ (c); |
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214 | bool lessZero= (sign (NTLc) == -1); |
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215 | if (lessZero) |
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216 | NTL::negate (NTLc, NTLc); |
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217 | ZZ NTLnum, NTLden; |
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218 | if (ReconstructRational (NTLnum, NTLden, NTLc, NTLq, bound, bound)) |
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219 | { |
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220 | if (lessZero) |
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221 | NTL::negate (NTLnum, NTLnum); |
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222 | CanonicalForm num= convertNTLZZX2CF (to_ZZX (NTLnum), Variable (1)); |
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223 | CanonicalForm den= convertNTLZZX2CF (to_ZZX (NTLden), Variable (1)); |
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224 | On (SW_RATIONAL); |
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225 | result += power (x, i.exp())*(num/den); |
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226 | Off (SW_RATIONAL); |
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227 | } |
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228 | } |
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229 | else |
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230 | #endif |
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231 | result += power( x, i.exp() ) * Farey_n(c,q); |
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232 | } |
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233 | else |
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234 | result += power( x, i.exp() ) * Farey(c,q); |
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235 | } |
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236 | if (is_rat) On(SW_RATIONAL); |
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237 | return result; |
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238 | } |
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239 | |
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