1 | /**************************************** |
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2 | * Computer Algebra System SINGULAR * |
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3 | ****************************************/ |
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4 | /* $Id: shiftgb.cc,v 1.4 2008-02-15 17:14:23 levandov Exp $ */ |
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5 | /* |
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6 | * ABSTRACT: kernel: utils for shift GB and free GB |
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7 | */ |
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8 | |
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9 | #include "mod2.h" |
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10 | |
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11 | #ifdef HAVE_PLURAL |
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12 | #include "febase.h" |
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13 | #include "ring.h" |
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14 | #include "polys.h" |
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15 | #include "numbers.h" |
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16 | #include "ideals.h" |
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17 | #include "matpol.h" |
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18 | #include "kbuckets.h" |
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19 | #include "kstd1.h" |
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20 | #include "sbuckets.h" |
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21 | #include "p_Mult_q.h" |
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22 | #include "kutil.h" |
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23 | #include "structs.h" |
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24 | #include "omalloc.h" |
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25 | #include "khstd.h" |
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26 | #include "kbuckets.h" |
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27 | #include "weight.h" |
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28 | #include "intvec.h" |
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29 | #include "structs.h" |
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30 | #include "kInline.cc" |
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31 | #include "stairc.h" |
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32 | #include "weight.h" |
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33 | #include "intvec.h" |
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34 | #include "timer.h" |
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35 | #include "shiftgb.h" |
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36 | #include "sca.h" |
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37 | |
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38 | |
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39 | #define freeT(A,v) omFreeSize((ADDRESS)A,(v+1)*sizeof(int)) |
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40 | |
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41 | poly pLPshift(poly p, int sh, int uptodeg, int lV) |
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42 | { |
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43 | /* assume shift takes place */ |
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44 | /* shifts the poly p by sh */ |
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45 | /* deletes p */ |
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46 | |
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47 | /* assume sh and uptodeg agree */ |
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48 | |
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49 | if (sh == 0) return(p); /* the zero shift */ |
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50 | |
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51 | poly q = NULL; |
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52 | poly pp = p; // pCopy(p); |
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53 | while (pp!=NULL) |
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54 | { |
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55 | q = p_Add_q(q, pmLPshift(pp,sh,uptodeg,lV),currRing); |
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56 | pIter(pp); |
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57 | } |
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58 | /* delete pp? */ |
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59 | /* int version: returns TRUE if it was successful */ |
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60 | return(q); |
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61 | } |
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62 | |
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63 | poly pmLPshift(poly p, int sh, int uptodeg, int lV) |
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64 | { |
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65 | /* pm is a monomial */ |
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66 | |
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67 | if (sh == 0) return(p); /* the zero shift */ |
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68 | |
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69 | if (sh < 0 ) |
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70 | { |
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71 | #ifdef PDEBUG |
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72 | Print("pmLPshift: negative shift requested"); |
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73 | #endif |
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74 | return(NULL); /* violation, 2check */ |
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75 | } |
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76 | |
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77 | int L = pmLastVblock(p,lV); |
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78 | if (L+sh-1 > uptodeg) |
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79 | { |
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80 | #ifdef PDEBUG |
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81 | Print("pmLPshift: too big shift requested"); |
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82 | #endif |
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83 | return(NULL); /* violation, 2check */ |
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84 | } |
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85 | int *e=(int *)omAlloc0((currRing->N+1)*sizeof(int)); |
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86 | int *s=(int *)omAlloc0((currRing->N+1)*sizeof(int)); |
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87 | pGetExpV(p,e); |
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88 | number c = pGetCoeff(p); |
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89 | int j; |
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90 | for (j=1; j<=currRing->N; j++) |
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91 | { |
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92 | if (e[j]) |
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93 | { |
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94 | s[j + (sh*lV)] = e[j]; /* actually 1 */ |
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95 | } |
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96 | } |
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97 | poly m = pOne(); |
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98 | pSetExpV(m,s); |
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99 | /* pSetm(m); */ /* done in the pSetExpV */ |
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100 | /* think on the component */ |
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101 | pSetCoeff0(m,c); |
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102 | freeT(e, currRing->N); |
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103 | freeT(s, currRing->N); |
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104 | return(m); |
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105 | } |
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106 | |
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107 | int pLastVblock(poly p, int lV) |
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108 | { |
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109 | /* returns the number of maximal block */ |
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110 | /* appearing among the monomials of p */ |
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111 | /* the 0th block is the 1st one */ |
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112 | poly q = p_Copy(p,currRing); /* need it ? */ |
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113 | int ans = 0; |
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114 | int ansnew = 0; |
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115 | while (q!=NULL) |
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116 | { |
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117 | ansnew = pmLastVblock(q,lV); |
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118 | ans = si_max(ans,ansnew); |
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119 | pIter(q); |
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120 | } |
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121 | /* do not need to delete q */ |
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122 | return(ans); |
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123 | } |
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124 | |
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125 | int pmLastVblock(poly p, int lV) |
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126 | { |
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127 | /* for a monomial p, returns the number of the last block */ |
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128 | /* where a nonzero exponent is sitting */ |
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129 | int *e=(int *)omAlloc0((currRing->N+1)*sizeof(int)); |
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130 | pGetExpV(p,e); |
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131 | int j,b; |
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132 | j = currRing->N; |
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133 | while ( (!e[j]) && (j>=1) ) j--; |
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134 | if (j==0) |
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135 | { |
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136 | #ifdef PDEBUG |
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137 | Print("pmLastVblock: unexpected zero exponent vector"); |
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138 | PrintLn(); |
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139 | #endif |
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140 | return(j); |
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141 | } |
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142 | b = (int)(j/lV) + 1; /* the number of the block, >=1 */ |
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143 | return (b); |
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144 | } |
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145 | |
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146 | int isInV(poly p, int lV) |
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147 | { |
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148 | if (lV <= 0) return(0); |
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149 | /* returns 1 iff p is in V */ |
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150 | /* that is in each block up to a certain one there is only one nonzero exponent */ |
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151 | /* lV = the length of V = the number of orig vars */ |
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152 | int *e = (int *)omAlloc0((currRing->N+1)*sizeof(int)); |
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153 | int b = (int)(currRing->N)/lV; /* the number of blocks */ |
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154 | int *B = (int *)omAlloc0((b+1)*sizeof(int)); /* the num of elements in a block */ |
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155 | pGetExpV(p,e); |
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156 | int i,j; |
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157 | for (j=1; j<=b; j++) |
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158 | { |
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159 | /* we go through all the vars */ |
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160 | /* by blocks in lV vars */ |
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161 | for (i=(j-1)*lV + 1; i<= j*lV; i++) |
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162 | { |
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163 | if (!e[i]) B[j] = B[j]+1; |
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164 | } |
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165 | } |
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166 | j = b; |
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167 | // while ( (!B[j]) && (j>=1)) j--; |
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168 | for (j=b; j>=1; j--) |
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169 | { |
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170 | if (B[j]!=0) break; |
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171 | } |
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172 | |
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173 | if (j==0) |
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174 | { |
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175 | /* it is a zero exp vector, which is in V */ |
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176 | return(1); |
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177 | } |
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178 | /* now B[j] != 0 */ |
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179 | for (j; j>=1; j--) |
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180 | { |
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181 | if (B[j]!=1) |
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182 | { |
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183 | return(0); |
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184 | } |
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185 | } |
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186 | return(1); |
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187 | } |
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188 | |
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189 | /* shiftgb stuff */ |
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190 | |
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191 | |
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192 | /* remarks: cleanT : just deletion |
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193 | enlargeT: just reallocation */ |
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194 | |
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195 | #endif |
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