Opened 12 years ago
Closed 12 years ago
#338 closed bug (invalid)
Difference between x*d-d*x and xd-dx in Plural
| Reported by: | Owned by: | somebody | |
|---|---|---|---|
| Priority: | critical | Milestone: | 3-1-4 and higher |
| Component: | dontKnow | Version: | 3-1-3 |
| Keywords: | Plural, parsing, ring | Cc: | viktor.levandovskyy@… |
Description
I typed the following code:
ring R = 0,(x,d),dp;
def r = nc_algebra (1,1); setring(r); xd-dx;
0
x*d-d*x;
-1
It should be the same result, namely -1. But somehow Singular:Plural interprets the first expression as something commutative, which is wrong.
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please see "*-multiplication (plural)" at http://www.singular.uni-kl.de/Manual/3-1-3/sing_387.htm#SEC427