Opened 11 years ago
Last modified 11 years ago
#372 new bug
classify() from classify.lib gives a different result after simple transformation
Reported by: | steenpass | Owned by: | pfister |
---|---|---|---|
Priority: | minor | Milestone: | 3-1-4 and higher |
Component: | singular-libs | Version: | 3-1-3 |
Keywords: | classify.lib, student project | Cc: |
Description
> option(noloadLib); > LIB "classify.lib"; > ring r = 0, (x,y), ds; > poly f = x3y+xy4+y5; > classify(f); // this is correct About the singularity : Milnor number(f) = 11 Corank(f) = 2 Determinacy <= 8 Guessing type via Milnorcode: Z[k,12k+6r-1]=Z[1,11] Y[k,r,s]=Y[1,1,1] Computing normal form ... Arnold step number 19 The singularity x3y+xy4+y5 is R-equivalent to Z[11]. Milnor number = 11 modality = 1 x3y+xy4+y5 > map phi = r, -x+y, x+y; // this is a proper transformation > f = phi(f); > classify(f); About the singularity : Milnor number(f) = 11 Corank(f) = 2 Determinacy <= 8 Guessing type via Milnorcode: Z[k,12k+6r-1]=Z[1,11] Y[k,r,s]=Y[1,1,1] Computing normal form ... // ** int division with `/`: use `div` instead in line >> bb[rvar(x(1))] = x(1) - (2*gamma / (B - beta))*x(2);<< // ** int division with `/`: use `div` instead in line >> bb[rvar(x(2))] = x(2) - ((C - beta) / (2*gamma))*x(1);<< Arnold step number 24 The singularity 32x5 is R-equivalent to Z[1,-4]. Milnor number = 11 modality = 2 Initial condition failed: k>=0; r>=0; s>=0 k=1 r=-4 s=0 0 >
Replacing '/' by 'div' in the mentioned lines as suggested (which should also be done) doesn't solve this.
Change History (1)
comment:1 Changed 11 years ago by
Keywords: | student project added |
---|---|
Owner: | changed from somebody to pfister |
Note: See
TracTickets for help on using
tickets.