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4.22.4.26 hasFace

Syntax:
hasFace( cone c1, cone c2 )
Type:
int
Purpose:
1 iff c1 contains c2 as a face; 0 otherwise
Example:
 
intmat M[2][2]=
1,0,
0,1;
cone c=coneViaRays(M);
intmat N1[1][2]=
1,1;
cone d1=coneViaRays(N1);
hasFace(c,d1);
==> 0
intmat N2[1][2]=
0,1;
cone d2=coneViaRays(N2);
hasFace(c,d2);
==> 1

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