Back to Forum | View unanswered posts | View active topics





Post a reply
Username:
Note:If not registered, provide any username. For more comfort, register here.
Subject:
Message body:
Enter your message here, it may contain no more than 60000 characters. 

Smilies
:D :) :( :o :shock: :? 8) :lol: :x :P :oops: :cry: :evil: :twisted: :roll: :wink: :!: :?: :idea: :arrow: :| :mrgreen:
Font size:
Font colour
Options:
BBCode is ON
[img] is ON
[flash] is OFF
[url] is ON
Smilies are ON
Disable BBCode
Disable smilies
Do not automatically parse URLs
Confirmation of post
To prevent automated posts the board requires you to enter a confirmation code. The code is displayed in the image you should see below. If you are visually impaired or cannot otherwise read this code please contact the %sBoard Administrator%s.
Confirmation code:
Enter the code exactly as it appears. All letters are case insensitive, there is no zero.
   

Topic review - Obtaining injective modules with Singular
Author Message
Questionn
  Post subject:  Obtaining injective modules with Singular  Reply with quote
Hi,
I have not used singular before but read a bit in the book, but was not able to find the commands needed to produce indecomposable injective modules in a given commutative ring.
Given a ring R, any such indecomposable injective module is isomorphic to the injective envelope of a module of the form R/p for a prime ideal p. So the input is a ring R together with a prime ideal p and the output should be the injective envelope of the module R/p. How can this be done with singular?

For example one could take R to be the polynomial ring in two variables over the complex numbers and for p a prime ideal generated by some polynomials.

Thank you for the help
Post Posted: Wed Sep 16, 2020 11:23 pm


It is currently Fri May 13, 2022 10:54 am
cron
Powered by phpBB © 2000, 2002, 2005, 2007 phpBB Group